Metoda nextInt() razreda Random vrne naslednjo psevdonaključno, enakomerno porazdeljeno int vrednost iz zaporedja generatorja naključnih števil.
Sintaksa
public int nextInt()
Parametri
TO
Povratna vrednost
Metoda nextInt() vrne naslednjo psevdonaključno int vrednost, izvlečeno iz zaporedja generatorja naključnih števil.
Primer 1
import java.util.Random; public class JavaRandomNextIntExample1 { public static void main(String[] args) { Random random = new Random(); //return the next pseudorandom integer value Integer val = random.nextInt(); System.out.println('Random Integer value : '+val); Integer val1 = random.nextInt(); System.out.println('Random Integer value : '+val1); } } Preizkusite zdaj Izhod:
Random Integer value : -298063488 Random Integer value : 1400961289
Metoda Java Random nextInt().
Metoda nextInt(int n) razreda Random vrne psevdonaključno vrednost int med ničlo (vključno) in podano vrednostjo (izključno), izvlečeno iz zaporedja generatorja naključnih števil.
Sintaksa
public int nextInt(int n)
Parametri
n : To je meja naključnega števila, ki ga je treba vrniti. Mora biti pozitiven.
Povratna vrednost
Metoda nextInt() vrne naslednjo psevdonaključno vrednost int med ničlo in n, ki je izvlečena iz zaporedja generatorja naključnih števil.
Meti
Metoda nextInt() vrže izjemo IllegalArgumentException, če n ni pozitiven.
Primer 2
import java.util.Random; public class JavaRandomNextIntExample2 { static int j=1; public static void main(String[] args) { Random random = new Random(); for (int i=1;i<8;i++) { return the next pseudorandom integer value val="random.nextInt(i);" system.out.println(j++ +'. random intvalue : '+val+' '); } < pre> <span> Test it Now </span> <p> <strong>Output:</strong> </p> <pre> 1. Random intvalue : 0 2. Random intvalue : 1 3. Random intvalue : 0 4. Random intvalue : 3 5. Random intvalue : 1 6. Random intvalue : 0 7. Random intvalue : 0 </pre> <h2>Example 3</h2> <pre> import java.util.Random; import java.util.Scanner; import java.util.concurrent.ArrayBlockingQueue; public class JavaRandomNextIntExample3 { static int j=1; public static void main(String[] args) { Scanner scanner = new Scanner(System.in); System.out.print('Enter number of players.'); int capacity = scanner.nextInt(); ArrayBlockingQueue queue = new ArrayBlockingQueue(capacity); System.out.println('Enter name of ' + capacity + ' Players.'); for (int i = 0; i <capacity; i++) { system.out.print(j++ + ' '); string str="scanner.next();" queue.add(str); } j="1;" random random(); for (string xyz : queue) integer val="random.nextInt(capacity);" system.out.println(j++ +'. +xyz+' will have '+val+' bonus points.'); < pre> <span> Test it Now </span> <p> <strong>Output:</strong> </p> <pre> Enter number of players.3 Enter name of 3 Players. 1 Sukla 2 Mukta 3 Amar 1. Sukla will have 0 bonus points. 2. Mukta will have 1 bonus points. 3. Amar will have 2 bonus points. </pre> <h2>Example 4</h2> <pre> import java.util.Random; public class JavaRandomNextIntExample4 { public static void main(String[] args) { Random random = new Random(); //return the next pseudorandom integer value Integer val = random.nextInt(0); System.out.println('Random Integer value : '+val); } } </pre> <span> Test it Now </span> <p> <strong>Output:</strong> </p> <pre> Exception in thread 'main' java.lang.IllegalArgumentException: bound must be positive atjava.util.Random.nextInt(Random.java:388) at com.javaTpoint.JavaRandomNextIntExample4.main(JavaRandomNextIntExample4.java:9) </pre> <h4>Note: The bound value must be positive else it will give IllegalArgumentException.</h4></capacity;></pre></8;i++)> Primer 3
import java.util.Random; import java.util.Scanner; import java.util.concurrent.ArrayBlockingQueue; public class JavaRandomNextIntExample3 { static int j=1; public static void main(String[] args) { Scanner scanner = new Scanner(System.in); System.out.print('Enter number of players.'); int capacity = scanner.nextInt(); ArrayBlockingQueue queue = new ArrayBlockingQueue(capacity); System.out.println('Enter name of ' + capacity + ' Players.'); for (int i = 0; i <capacity; i++) { system.out.print(j++ + \' \'); string str="scanner.next();" queue.add(str); } j="1;" random random(); for (string xyz : queue) integer val="random.nextInt(capacity);" system.out.println(j++ +\'. +xyz+\' will have \'+val+\' bonus points.\'); < pre> <span> Test it Now </span> <p> <strong>Output:</strong> </p> <pre> Enter number of players.3 Enter name of 3 Players. 1 Sukla 2 Mukta 3 Amar 1. Sukla will have 0 bonus points. 2. Mukta will have 1 bonus points. 3. Amar will have 2 bonus points. </pre> <h2>Example 4</h2> <pre> import java.util.Random; public class JavaRandomNextIntExample4 { public static void main(String[] args) { Random random = new Random(); //return the next pseudorandom integer value Integer val = random.nextInt(0); System.out.println('Random Integer value : '+val); } } </pre> <span> Test it Now </span> <p> <strong>Output:</strong> </p> <pre> Exception in thread 'main' java.lang.IllegalArgumentException: bound must be positive atjava.util.Random.nextInt(Random.java:388) at com.javaTpoint.JavaRandomNextIntExample4.main(JavaRandomNextIntExample4.java:9) </pre> <h4>Note: The bound value must be positive else it will give IllegalArgumentException.</h4></capacity;> Primer 4
import java.util.Random; public class JavaRandomNextIntExample4 { public static void main(String[] args) { Random random = new Random(); //return the next pseudorandom integer value Integer val = random.nextInt(0); System.out.println('Random Integer value : '+val); } } Preizkusite zdaj Izhod:
Exception in thread 'main' java.lang.IllegalArgumentException: bound must be positive atjava.util.Random.nextInt(Random.java:388) at com.javaTpoint.JavaRandomNextIntExample4.main(JavaRandomNextIntExample4.java:9)