The nadaljevanje izjave v jeziku C se uporablja za postavitev krmilnika programa na začetek zanke. Stavek continue preskoči nekaj vrstic kode znotraj zanke in nadaljuje z naslednjo ponovitvijo. Uporablja se predvsem za pogoj, tako da lahko preskočimo nekaj kod za določen pogoj.

Sintaksa:

 //loop statements continue; //some lines of the code which is to be skipped 

Nadaljujte s primerom izjave 1

 #include void main () { int i = 0; while(i!=10) { printf('%d', i); continue; i++; } } 

Izhod

 infinite loop 

Nadaljujte s primerom izjave 2

 #include int main(){ int i=1;//initializing a local variable //starting a loop from 1 to 10 for(i=1;i<=10;i++){ if(i="=5){//if" value of i is equal to 5, it will continue the loop continue; } printf('%d 
',i); end for return 0; < pre> <p> <strong>Output</strong> </p> <pre> 1 2 3 4 6 7 8 9 10 </pre> <p>As you can see, 5 is not printed on the console because loop is continued at i==5.</p> <h2>C continue statement with inner loop</h2> <p>In such case, C continue statement continues only inner loop, but not outer loop.</p> <pre> #include int main(){ int i=1,j=1;//initializing a local variable for(i=1;i<=3;i++){ for(j="1;j&lt;=3;j++){" if(i="=2" && j="=2){" continue; will continue loop of only } printf('%d %d
',i,j); end for return 0; < pre> <p> <strong>Output</strong> </p> <pre> 1 1 1 2 1 3 2 1 2 3 3 1 3 2 3 3 </pre> <p>As you can see, 2 2 is not printed on the console because inner loop is continued at i==2 and j==2.</p> <hr></=3;i++){></pre></=10;i++){>

Kot lahko vidite, 5 ni natisnjen na konzoli, ker se zanka nadaljuje pri i==5.

Stavek C continue z notranjo zanko

V takem primeru stavek C continue nadaljuje samo notranjo zanko, ne pa tudi zunanje zanke.

 #include int main(){ int i=1,j=1;//initializing a local variable for(i=1;i<=3;i++){ for(j="1;j&lt;=3;j++){" if(i="=2" && j="=2){" continue; will continue loop of only } printf(\'%d %d
\',i,j); end for return 0; < pre> <p> <strong>Output</strong> </p> <pre> 1 1 1 2 1 3 2 1 2 3 3 1 3 2 3 3 </pre> <p>As you can see, 2 2 is not printed on the console because inner loop is continued at i==2 and j==2.</p> <hr></=3;i++){>

Kot lahko vidite, 2 2 ni natisnjen na konzoli, ker se notranja zanka nadaljuje pri i==2 in j==2.